Why the electric field of an infinity line is dependent on distance? A very common question about Gauss law is being asked in schools or Internet: 

Why the electric field of an infinite plane is independent on distance?  

Actually I was one of who asked this question and I found an answer,  and I will explain it in the next paragraph.
A very important thing we have to remember when think about this kind of problems is that the electric field is a vector, and the $Ex$ vector only effect on it because $Ey$ is cancelled by another charge.
Since we go further. the electric field is being weaker, also the angle $θ$ is being less too So $\cos θ$ is getting larger so that compensated the lack of electric field.

Now, why we cant apply this argument on an infinite line, as you see in the picture?

Please don't explain it using Gauss law because it's hard to visualize it, because the number of imaginary concepts like : (Flux,  Electric field,  epsilon ... etc.) So it's hard to realize.
Finally,  please don't mark my question as a duplicate because I didn't understand Eeko explanation.
Why does the electric field of an infinite line depend on the distance, but not on an infinite plane?
 A: One way to think about this is through symmetry.  If your plane is infinite then as you move away from it, nothing appears to change.  Exactly half of your field of view is filled with plane.
Here's another way to look at it:
Take your cone of view.  If I double the distance from the plane, the charge in that cone is twice as far away.  Inverse square -- you get 1/4 of the contribution to the electric field.  
But your cone is now grabbing a circle of plane that is twice the diameter => 4 times the area, so the contribution is 4 times as much.  Two factors balance out.
When you calculate this using a simple integral, you figure it out usually integrating over your angle from 0 to 90.  Part of this you figure out the differential amount of charge in the plane for $\delta\theta$ and when you do the distance from the plane cancels out.
A: You're correct that there is no electric field parallel to the line, since the line is symmetric across any point you pick. (A benefit of being infinite in length). But that isn't enough to say that the electric field doesn't vary with distance perpendicular to the line.
If you look at the diagram for the infinite plane, you'll see that as you look at larger and larger angles, the circumference of the ring of charges you consider grows in proportion to the sin($\theta$). The line on the other hand, only has two points of charge for any angle $\theta$, so rather than growing with sin($\theta$), the contribution of charges to the electric field is independent of $\theta$. 
Since, as you noted, the electric field is constant for an infinite plane, it makes sense that the electric field of an infinite line should decrease with distance, as the amount of contributing charge in the plane is more than in the line.
