This is a drawing of a spherical conductor with a hollow center. The black dots represent +ive charges, and the arrows represent their electric fields. I am assuming the black dots start on the inner surface. Imagining each position of the inner surface as a plane or sheet, the +ive charge should exert fields in all directions.
My question: Is the reason that the charges relocate to the outer surface because inside the hollow space, the fields pointed center-wise cancel out? This leaves only the field lines pointing outside the sphere, and the +ive charges will continue along the field lines until they can travel no longer. Thus charges in a conductor don't just move to any surface, they must move to the outermost surface.
I know it is common for people to draw conducting +ive spheres with fields just pointing normally outwards from the outer surface. I am wondering if this is because although the surface is much like a sheet with fields pointing both out and into the sphere, we just assume the fields pointing inwards cancel?
By this logic, a conducting sphere of radius R should (rightly) have the same field as a conducting thin spherical shell of radius R.