1
$\begingroup$

In Haldane's original paper [5], he discusses the quantum anomalous Hall effect as being characterized by the so-called Chern number that is the surface integral of Berry curvature over the entire parameter space.

Now, the quantum spin Hall effect [2] requires a model with spin, and could be characterized by the so-called spin Chern number [3]. From Figure 1 in [4] (that follows this paragraph), I understood that the spin Chern number can be thought of as the difference between sums of an integer characterizing spin up and spin down channels:

https://arxiv.org/pdf/1301.4113.pdf

Now, this figure plots the local Berry curvature over a manifold. However, Haldane's model also can give rise to such figures (with peaks at the Dirac points), with different configurations for different topological phases*.

My question is, how do I make sense of the Haldane model's spin Chern number given the fact that is a spineless model (at least in the original paper's approximations). In Figure 1 d) above, which could apply to the Haldane model, the spin Chern number Cs is = 0. Is this always the case? Or does it depend on the sign of the Berry curvature at the Dirac singularity? If it is always = 0, does it make sense to talk about only part of the manifold that includes only one Dirac point?

Clearly, I am confused with certain ideas, so I would appreciate any clarifications/resources.

  • I thought that a key feature of the Haldane model was that the Berry curvature of a level is the opposite of the other - however this does not agree with d) above. Perhaps it is my misunderstanding of what a spin channel means, then?

[5] https://journals.aps.org/prl/pdf/10.1103/PhysRevLett.61.2015

[2] https://en.wikipedia.org/wiki/Quantum_spin_Hall_effect

[3] https://arxiv.org/pdf/cond-mat/0603054.pdf

[4] https://arxiv.org/pdf/1301.4113.pdf

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.