# How an operator is converted to a function? [closed]

$$\langle m|F|n\rangle^*=\langle F(n)|m\rangle$$ How does the operator become a function of state $$|n\rangle$$?

• For <m|F|n>*=<F(n)|m> – TA Run Mar 31 '19 at 12:08

Since $$\langle m|F|n\rangle^* = \langle n| F^\dagger |m\rangle$$ we can rename the left side into a new bra vector $$\langle F(n)| := \langle n | F^\dagger$$. There is really no math or physics happening here, only a renaming of terms.