0
$\begingroup$

I have read that a normal force acts on an object kept on a surface in a direction opposite to the force applied by the object on the surface.

My question is : Can normal force appear in other cases. Like when we want to push a block horizontally we apply a force. Can that force be called a normal force ?

Thanks in advance.

$\endgroup$
1
  • 1
    $\begingroup$ Think of the normal force as the force that keeps solid objects from passing through each other. It shows up all over whether you are holding a pencil or trying to walk through a wall. $\endgroup$
    – M. Enns
    Mar 30, 2019 at 16:44

2 Answers 2

0
$\begingroup$

The "normal force" is essentially just electrostatic repulsion between two objects that are very close together. We usually simplify it to "normal force" because the force is "normal" (perpendicular) to the flat surface of contact.

So, I guess you could say when you push on a block the force between you and the block is a normal force. Just keep in mind it's a macroscopic description of microscopic phenomena.

$\endgroup$
3
  • $\begingroup$ You need to give a little more detail in the problem you described. A block you are pushing on. $\endgroup$
    – Natsfan
    Mar 30, 2019 at 15:52
  • $\begingroup$ @jmh Is this meant for the OP? $\endgroup$ Mar 30, 2019 at 16:16
  • $\begingroup$ Yes, sorry... I forgot to signify that. I posted this before any answers showed up. $\endgroup$
    – Natsfan
    Mar 30, 2019 at 16:54
0
$\begingroup$

Yes, but you have to take the normal component of your push. If your push is perpendicular to the surface then the whole force is a normal force. Normal force refers to a contact force which is what you are describing. This, as Aaron Stevens pointed out, is in the macroscopic regime.

$\endgroup$

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service and acknowledge that you have read and understand our privacy policy and code of conduct.

Not the answer you're looking for? Browse other questions tagged or ask your own question.