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In QM textbooks the single step potential problem is explained in great detail. However, it is hard to understand what happens when $V_{0}<0$. Could anyone please explain qualitatively, how the incident wave, transmitted wave, and the reflected wave behave?
$V(x) = 0 (x > 0)$
$V(x) = V_{0}, V_{0}<0, (x \le 0)$

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The zero of potential can be shifted up and down arbitrarily. What matters is the difference E-V, where E is the kinetic energy of the particle. The solution is the same.

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  • $\begingroup$ Isn't there any difference between step-up and step-down cases? $\endgroup$ – Nownuri Mar 29 at 23:13

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