# Magnetic field inside a conductor

We know there is an energy associated with magnetic fields is $$\frac{1}{2}\mu B^2$$ Consider a magnetic field perpendicular to a conductor (any metal). Shouldn't it theoretically be possible to make magnetic field inside the metal $$0$$ (similar to the way the electric field inside a metal is $$0$$ by redistributing charges) by creating circular current loops in the metal do oppose the magnetic field? This would minimize energy inside the metal right? Why does this not actually happen?

• It actually happens in superconductors. – flaudemus Mar 28 at 7:33

Relevant answer: Energy inside a material is given by summing all the contributions by each dipole moment whose energy is given by $$E= -\vec{m}\cdot\vec{B}$$
So 0 is not the lowest energy. And the least energy is when $$m$$ and $$B$$ align.