I am a high school physics student and I have a question on part (a) regarding the conservation of linear momentum. It says to use the conservation of linear momentum to solve for the velocity of the rod after collision, but I find that kind of skeptical since the distance from the center of mass is not taken into account. Shouldn't the velocity of the rod after collision be dependent on where the rod is hit (the center of the rod as opposed to the end)? I think that it should take distance from the CM into account since most of the initial momentum could get translated into angular momentum rather than linear momentum if the rod is hit at the end, but I could be wrong. This is assuming that there are no external forces and the rod is on a frictionless horizontal surface.

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    $\begingroup$ The linear velocity of the center of mass of the rod will just depend on the linear momentum of the mass that hits it. Linear momentum and angular momentum are different physical things, so you can't convert between the two. $\endgroup$ – BioPhysicist Mar 23 '19 at 2:26
  • $\begingroup$ Depending on trajectory of the hitting object, it will transfer different amounts of kinetic energy, both linear and angular momenta to the rod, that would then have these different amounts of these respective quantities. Note that any moving object has a nonzero angular momentum, unless it is on a linear trajectory passing the coordinate system origin. $\endgroup$ – Poutnik Mar 23 '19 at 5:01
  • $\begingroup$ P.S.: .. unless the the position related and rotation related momentum cancel each other, of course. $\endgroup$ – Poutnik Mar 23 '19 at 5:06
  • $\begingroup$ Thank you guys for the help! $\endgroup$ – LVST Mar 23 '19 at 17:31

The velocity of the rod is fully determined by the change of velocity of the hitting object and related momentum exchange.

As Aaron correctly says, momentum and angular momentum are 2 independent, non interchangeable quantities.

The distance is taken into account. If the object would hit the rod at other than L/6 height, the return velocity would not be -v/2.

The final velocities of both object depend on where the rod was hit.

The maximum of total translational energy occurs, if the rod is hit at the middle. In such a case, no energy is spent on its rotation.

The minimum of the total translational energy occurs, if the rod is hit at the end. In such a case, the big part of energy is spent on its rotation.

Note that for angular momentum conservation, all motion must be considered, not just rotation.


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