So I came across the single slit interference in which a parallel beam of light is passed through narrow slit as shown in figure below. (I made only 3 rays in figure for simplicity there are actually infinite of them)
I have a confusion regarding the derivation of the condition of minima or destructive interference(as mentioned in picture).
My textbook derived it by giving an example, say when dsin(theta) = 2(wavelength of monochromatic light) , here d is the slit width.
1) First divide the slit into four parts. (By making three imaginary lines which divides it into equal four parts having width d/4)
2) Then for every point in any of the parts there will be another one located at a distance d/4 the ray passing through these points will interfere destructively.
3) The whole slit can be divided into such pairs of rays and thus the whole summation (I don't know but I have a feeling that instead of this approach these relations can be derived using integral calculus) of rays interfere destructively. Thus at this angle satisfying the above relation, minima occurs.
The problem is that I can, instead of dividing the slit into four parts, divide slit into TWO PARTS and prove that Maxima occurs at this angle satisfying the relation above.
When slit is divided into two parts then for every point in any of the two rigions there will be another one seperated by distance d/2 and will interfere constructively! How's that possible!? What's wrong in dividing slit into 2 parts instead of 4?
Please tell me the error in my argument (this is making my head hurt) and if possible, is there's another way to get this condition using rigorous method (integral calculus)?
Any help will be appreciated.
