I'm reading about Perelomov coherent states, but I'm not sure if I'm getting it right. From this question and some Perelomov papers I understand the following:

The Perelomov coherent states are generated by applying a unitary operator to a certain state. If we have an arbitrary 1D Hamiltonian $H = \frac{p^2}{2m} + V(x)$, then the corresponding generalized coherent states would be generated as:

$$|\alpha(x,p)\rangle = \hat{T}(x, p)|0\rangle$$

Where $\hat{T}(x, p) = \exp(i(x\hat{p} - p\hat{x}))$ is the translation operator. The idea between this is that if $|0\rangle$ is the ground state, then it also would be the state that has minimum $\Delta x\Delta p$. So we move it on the phase space so that is has some momentum and it's some length away from the equilibrium point.

Am I right? Is this how 1D general coherent states are generated?


1 Answer 1


The key point is the algebra of your observables and the resulting group.

If you work with $\hat x,\hat p$ and $\hat 1$ this is the HW group, and Perelomov shown that translating the h.o. vacuum state gives the same as the original Glauber coherent states. Indeed in this case the CS is just a Gaussian displaced so that $\langle x\rangle$ and $\langle p\rangle$ need not be $0$.

If you work with angular momentum operators then the translation is a translation on the sphere, i.e. a rotation, and CS are rotated “ground states”. The ground state is either the state with $m=j$ or $m=-j$.

This is the essence of the Perelomov coherent states: you have a fiducial state and you act on it by a generalized displacement, which is a group transformation, and the group comes from the algebra of observables. Thus one can define $SU(1,1)$ coherent states, as discussed in Perelomov’s book, and pretty much any type of coherent state in this manner.

There is another key feature. It is known that, if the fiducial state is highest (or lowest) weight for the irrep of the group, then the whole geometrical setuo comes with a natural Poisson bracket on the appropriate manifold, i.e. the CS also naturally live in the classical phase space for this system since they are parametrized by points in the phase space. (The manifold is actually a coset space closely tied to the invariance properties of the fiducial state.). Hence these nice drawings either in the plane (for HW) or on the sphere (for angular momentum) where CS are mapped to localized lumps centered at the phase space coordinate of the CS.

There’s a nice review

Zhang, Wei-Min, and Robert Gilmore. "Coherent states: theory and some applications." Reviews of Modern Physics 62.4 (1990): 867.

and Bob Gilmore has published quite a bit of pedagogical work in the 80’s, v.g.

Gilmore, Robert. "Coherent states for bosons and fermions: A tutorial." Progress in Particle and Nuclear Physics 9 (1983): 479-494.

There are quite nice geometrical generalizations, such as vector coherent states, but these are much more sophisticated: see

Bartlett, Stephen D., David J. Rowe, and Joe Repka. "Vector coherent state representations, induced representations and geometric quantization: II. Vector coherent state representations." Journal of Physics A: Mathematical and General 35.27 (2002): 5625.

Saturation of the Heisenberg relations is a bonus and is “baked in”: fiducial vectors have this property in general and you’re just displacing this vector so with some suitable definition of observables one easily recovers this property. See

Delbourgo, Robert, and J. R. Fox. "Maximum weight vectors possess minimal uncertainty." Journal of Physics A: Mathematical and General 10.12 (1977): L233.

  • $\begingroup$ I was thinking more about staying on the HW group but choosing a different Hamiltonian. Given the Coulomb 1-D Hamiltonian $H = p^2/2m + l^2/2r^2 - k/r$ for example, then the coherent states would be $\hat{T}(x, p)$ acting on the QHO ground state or acting on the Coulomb ground state? If we want minimum uncertainty then the "right" state would be the QHO ground state? $\endgroup$
    – lytex
    Commented Mar 16, 2019 at 11:47
  • $\begingroup$ The strict definition would not work for this case, at least I don’t think, but you might find something directly useful in this older paper by Klauder ( arxiv.org/abs/quant-ph/9511033) and also in the work of Veronique Hussin on coherent states. $\endgroup$ Commented Mar 16, 2019 at 13:55
  • $\begingroup$ For minimum uncertainty states use keyword “intelligent states” in GoogleScholar. $\endgroup$ Commented Mar 16, 2019 at 14:00
  • $\begingroup$ These type of coherent states, in principle for an arbitrary Hamiltonian with pure point spectrum, are the Gazeau-Klauder coherent states. I'm not 100% sure if they are also valid when the classical Hamiltonian doesn't have action-angle variables, which is why I startted to investigate the Perelomov coherent states in the first place. Very interesting papers nonetheless. $\endgroup$
    – lytex
    Commented Mar 16, 2019 at 16:30

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