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I'm trying to solve a problem where I have an object resting on an inclined plane, with the angle of the plan being alpha, and the weight being w. I'm having trouble figuring out how I can calculate the component of the weight parallel to the plane. I also want to find out the weight component perpendicular to the plane.

I don't want an outright answer, more of an explanation to help me understand. Thanks!

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  • $\begingroup$ John, what is Your school background, especially what about math? $\endgroup$
    – Georg
    Commented Feb 5, 2011 at 19:33
  • $\begingroup$ I need a sketch tool that's really handy for questions like this. $\endgroup$ Commented Feb 5, 2011 at 20:49
  • $\begingroup$ @dmckee: try pencil and paper :) $\endgroup$
    – Marek
    Commented Feb 5, 2011 at 21:29
  • $\begingroup$ @Marek: Thanks. I'm partial to white boards, myself. $\endgroup$ Commented Feb 5, 2011 at 21:32
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    $\begingroup$ @dmckee: but I really meant it. If you have a scanner (or even just a digital camera) at your disposal, I don't think there's any quicker way than drawing with hand. Though white board would do the trick too, I suppose. Personally, I like drawing stuff on my windows. It produces cool math/phys shadows too :) $\endgroup$
    – Marek
    Commented Feb 5, 2011 at 22:16

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Here's a quick sketch: enter image description here

Gravity is the vector $u$. Its components in the plane and against the plane are $v$ and $w$ respectively. You want to find $v$.

The angle between the plane and horizontal is the same as the angle between $w$ and $u$, which allows you to find a simple trig relation to solve the problem.

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Imagine the inclined plane, and imagine an arrow pointing straight down, representing your weight (the force of gravity). Then imagine rotating that picture so that the plane is horizontal, with the arrow rotated sideways by alpha. Imagine now a horizontal x axis, and a vertical y axis, like they always draw in the textbooks. The x and y axes should cross (intersect) at the tail of the weight arrow. Now imagine a horizontal line that starts at the tip of the arrow, and ends at the (vertical) y axis. That line is the component of the weight that is parallel to the inclined plane.

Then use what you know about sines and cosines (trigonometry) to calculate the amount of weight in the directions parallel and perpendicular to the incline.

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Here's an animation which shows how to keep the triangle correct when working incline plane problems. Hope this helps... The red lines are parallel.

Inclined Plane Problem

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  • $\begingroup$ Answers consisting only (or primarily) of a link to another resource are treated as non-answers in the Stack Exchange model. We're not a link farm here, we're trying to be a repository of well answered good questions. Moreover, link shorteners are strongly discouraged, as they hide information about where the link is taking the clicker. $\endgroup$ Commented Jun 18, 2016 at 17:16

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