Resultant force from two lever arms held together at a fixed angle, weight hung on one arm

Trying to determine the resultant force F with the setup pictured below, given that L1, L2, and theta can vary. Not sure how to translate the torque applied by the weight to the force at L1. Thanks in advance!

• You haven't specified how $L_2$ is positioned with respect to the horizontal. – PiKindOfGuy Feb 27 at 4:21
• If $\theta$ were $\pi/2$ then I would naturally assume that $L_2$ is horizontal, but as it stands, I don't know. – PiKindOfGuy Feb 27 at 4:22
• What way do you want to find the force, does the question demand that the system is in equilibrium? – think__tech Feb 27 at 15:57

If so, then the torque from the weight and the torque from the resistance must sum to zero. $$\tau_1 + \tau_2 = 0$$
Do you know how to figure the torque from those two elements? Remember that torque is the perpendicular distance from the axis based on the direction of the force. The force on the L1 arm is not directed downward, it will be directed to the left. So the angle between the force and the vector from the axis would be $$\frac{\pi}{2}$$.