# Is specific volume a function of temperature only (in liquids)?

As far as I know, you can take the equation $$pv=RT$$ (with $$v$$ being the specific volume) for ideal gases. But I had a question in a quiz asking about this, and the answer was "dependent on temperature only" (for liquids, which ain't exactly ideal gases). I just can't find the right equation to prove this. What am I missing?

• Can you provide any additional information? The specific volume of liquids depends on pressure also (although to a lesser extent than gases), so the answer appears incorrect. – Chemomechanics Feb 25 '19 at 18:09
• There appears to be a disconnect. The equation applies only to ideal gases and has nothing to do with liquids. Please describe the quiz question in its entirety. – Bob D Feb 25 '19 at 18:20

Look at the schematised $$p,V,T$$ diagram of a non-ideal gas:
Left is the liquid area of the diagram. One can see that the volume has a small dependence on pressure (liquids are said to incompressible: $$\frac{\partial V}{\partial p} \approx 0$$) but has a stronger dependence on temperature.