# Dirac solution with coulomb-field (perturbation theory)

The dirac equation with some small gauge potential $$\epsilon \gamma^\mu{A}_\mu(x)$$ reads as $$(\gamma^\mu\partial_\mu-m+\epsilon\gamma^\mu A_\mu(x))\psi(x) = 0.$$

The solution up to first order is

$$\psi(x) = \psi_0(x) +\tau\int\frac{d^4p}{(2\pi)^4}\int d^4x'\frac{e^{-ip(x-x')}}{\gamma_\mu{p}^\mu-m} \gamma^\mu A_\mu(x')\psi_0(x')+\mathcal{O}(\tau^2).$$

How to solve this integral for the coulomb field?

There seems to be a problem with your question. You need to define all components of $$A_\mu(x)$$, so it is not clear so far what you are asking. Another thing. Even if we ignore the first problem, the expression for $$A(x)$$ does not depend on $$x$$, so the electromagnetic field vanishes. If this is indeed what you are interested in, you can use solutions for the free Dirac equation and apply a gauge transform.
EDIT (2/23/19): Your edited question also has its share of problems. What is $$x$$ in your definition of $$A(x)$$? If it is a 4-vector, then the definition does not make sense. If, however, it is the $$x$$ coordinate, then your $$A(x)$$ is a gradient of a scalar function, so the electromagnetic field vanishes, and you can use gauge-transformed solutions of the free Dirac equation.