# Minkowski diagram of two frames in rest with respect to each other

I'm starting to study Minkowski diagrams, but I can't figure out how should the axis of a $$S'$$ system look if it is in rest with respect to the frame $$S$$. I've seen that in all diagrams the origin seems to stay in place. How is this possible for two frames in rest to respect with each other, one separated from the other 8 light-minutes to agree on the origin? Shouldn't the other frame be "to the right/left"?

Also, if I am an observer on a frame $$S''$$ moving with a speed $$u_x$$ with respect to them, how would their axis look to me? Are they axis with the same inclination but located in different places?

• If two observers are at rest w/r to each other the axes of their respective diagrams will coincide since the relative slope is $v/c$, with $v$ the relative of one w/r to the other. – ZeroTheHero Feb 21 at 13:35
• But why ? Wouldn't that mean that an event A(x^0,x^i) would have the same coordinates in both frames? That's clearly false, since the frames are spatialy separated. – IchVerloren Feb 21 at 13:40
• Minkowsky diagram are usually constructed so that origins coincide. You would need to simply shift the origin of one but keep the relative orientations the same. – ZeroTheHero Feb 21 at 13:42