# Electron density Saha Ionization Equation

Saha-Boltzmann equation describes the ratio of number densities between any two consecutive ionization states and its product with the number electron density i.e.

$$n_e\frac{n_{i+1}}{n_{i}}$$

Here, $$n_e$$ is the electron number density, $$n_{i+1}$$ is the number density in $$i+1$$ ionization state and $$n_i$$ is the number density in the $$i$$ ionization state. My question is regarding the factor $$n_e$$. Which electron density is this actually? Is it the electron density produced as a result of ionization from $$i$$ state to $$i+1$$?

Is it the electron density produced as a result of ionization from $$i$$ state to $$i + 1$$?
Perhaps or perhaps not. Again, this is not the issue so much as $$n_{e}$$ corresponds to the total electron number density.
• As I said, it does not matter from where they came. Yes, $n_{e}$ is the number density of the free electrons in the plasma. – honeste_vivere Feb 19 at 15:24