Both the fundamental constants $\hbar$ and $c$ have dimensions. In particular, $[\hbar]=ML^2T^{-1}$ and $[c]=LT^{-1}$. But in natural units, we make them dimensionless constants of equal magnitude. How is this possible? This means length is measured in the same units as time which is measured in the units of inverse mass! Am I measuring the distance between two points in seconds??? Can we do that? I cannot make myself comfortable with it :-( Also why is it not possible to make $\hbar=c=G=1$ simultaneously?

  • $\begingroup$ Related: physics.stackexchange.com/questions/102527/… $\endgroup$
    – cxx
    Commented Feb 16, 2019 at 3:41
  • $\begingroup$ In US English, people measure distances in seconds all the time. "How far away is the city?" "Oh, about an hour." The "natural" speed in that case is different, though. $\endgroup$
    – rob
    Commented Feb 17, 2019 at 1:00

4 Answers 4


The other answers more directly address your questions, but I would point out that many people casually measure distance and time in the same units. If you've ever said "I live twenty minutes away from my office," then you've used units in which the characteristic speed (i.e. the conversion factor between distance and time - in this case, the average speed of traffic) has been set to 1.


Can we measure distance in seconds? Definitely. When you set $c=1$, “one second of distance” is simply the distance that light travels in vacuum in one second. And “one meter of time” is the amount of time it takes for light to go one meter in vacuum.

It is possible to set $\hbar=c=G=1$ simultaneously. This is what produces Planck units.

Natural units are not just a nice simplification. They allow the physics of an equation to “shine through” more clearly. For example,


says “Mass is the invariant length of the energy-momentum four vector” more clearly than

$$E^2-\mathbf{p}^2 c^2=m^2 c^4$$

does, with its extraneous factors of $c$.


But in natural units, we make them dimensionless constants of equal magnitude. How is this possible?

It is not widely known or appreciated, but both the magnitude and the dimensionality of the units we use are a matter of convention. We are free to use different unit systems with different conventions, as long as we use them self consistently. The most important thing to remember is that the laws of physics are slightly different if we write them in other units.

CGS units are the most widely used units with substantial differences in dimensionality compared to SI. For example, in SI units the Coulomb is a base unit with dimensions of $Q$, but in CGS units the statcoulomb is a derived unit with dimensions of $L^{3/2}M^{1/2}T^{-1}$. As a result, Coulomb’s law takes a particularly simple form: $$F=\frac{q_1 q_2}{r^2}$$

Am I measuring the distance between two points in seconds??? Can we do that?

Yes, but not in SI units. There are also units where time would have dimensions of length. Those are also valid. You simply have to adapt the equations appropriately.

Also why is it not possible to make ℏ=𝑐=𝐺=1 simultaneously?

It is. One example is Planck units https://en.m.wikipedia.org/wiki/Planck_units


I feel the previous answers don't completely answer the question, so I'm providing my own.

SI units were originally chosen with reference to constant quantities that we as humans could measure at the time they were defined. For example, when the metre was officially defined in 1793, it was as a fraction of the distance from the equator to the north pole. Once distance (and hence area and volume) were defined, many other units could be expressed using properties of materials: kilograms as the mass of a litre (0.001m^3) of water, amps in terms of forces between loops of metal wire... Other units such as air pressure were expressed relative to the pressure at sea level, and seconds are defined relative to the length of a day.

Of course all of these original definitions have flaws: determining the exact position of the (geographic) north pole and measuring the distance to it with any accuracy would have been hard enough in 1793, and even since gaining the technology to do it we know enough about the earth to expect that distance (and similarly air pressure at sea level) to fluctuate minutely over the course of a year or a century. Thus we replaced these original definitions with quantities derived from materials in carefully controlled conditions, which the consensus in physics assures us are universal, which is to say that reproducing the same conditions anywhere in the universe will give a measurement that agrees. Nonetheless, the relative scales of these definitions have been retained, so all SI units are determined by human experience.

However, the study of physics makes clear that there are more natural, fundamental ways to choose units independent of human experience. Since Einstein, relativity has taught us that light has a universal speed through which we can compare distances and times. This speed alone provides no fundamental unit of distance or time; in terms of SI units we get a constant $c$ that expresses the ratio of metres to light-seconds, for instance. The idea of natural units is that we rescale our measurements: perhaps we keep seconds to measure time, but we now measure distances in light seconds. This is the same as setting $c=1$. However, in this interpretation, $c$ is not dimensionless! Rather, it allows us to ignore dimensions because we implicitly correct the dimensionality of expressions by multiplying with powers of $c$ that we may now ignore numerically because $c=1$. Of course, if we ever want to use the resulting equations for real-world calculations in terms of the familiar units, we can use dimensional analysis to put the powers of $c$ back in.

The more fundamental constants we have, the fewer units we need to choose, as long as they don't clash. As pointed out in the other answers, we can rescale to make $c=\hbar=G=1$, but only because these quantities are dimensionally independent. If a revelation in physics produced a new fundamental speed $c'$ different from $c$, for example, then we of course couldn't rescale to make both of these 1.

I think the accepted answer here gives two good interpretations / explanations, the first of which is similar to mine.

  • $\begingroup$ “A purely natural system of units has all of its units defined ... such that the numerical values of the selected physical constants in terms of these units are exactly dimensionless 1.” - en.wikipedia.org/wiki/Natural_units (emphasis mine) $\endgroup$
    – G. Smith
    Commented Feb 16, 2019 at 17:02
  • $\begingroup$ @G.Smith As I stated in my answer, whether or not you retain dimensions is up to your interpretation; of course I can abstractly do all of the maths involved in my physics problem while ignoring dimensions, but I can't interpret my solution physically without putting them back in at some point (or implicitly keeping them throughout). $\endgroup$ Commented Feb 17, 2019 at 11:16
  • $\begingroup$ If I express a velocity $v=1/2$ in natural units, I of course mean $v=c/2$. I can work with $1/2$ as a dimensionless quantity to simplify my maths but then it isn't a velocity. $\endgroup$ Commented Feb 17, 2019 at 11:21

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