The following YouTube video from Sixty Symbols ( What is the maximum Bandwidth? - Sixty Symbols https://www.youtube.com/watch?v=0OOmSyaoAt0 )states that only a laser which always shines truly shines as a single frequency (df = (or ~=) 0). A laser which is active only long enough to send a good pulse of coherent light must contain all of the frequencies necessary to shorten that pulse, where df * dt =1. No need to mess with the frequencies present -- the nature of the thing will ensure that sufficient distribution of frequencies are present.
If I shine a laser pulse through a prism, intuition says that I still only get a single spectral line coming out. Is this consistent? Is my intuition wrong, and the pulse of coherent light will spread through the prism? Will there be spreading only at the start and end of the pulse, but sufficient? To my level of knowledge, this is not a duplicate of:
Light of a specific wavelength going through a prism
It is related related to this question, sprung from the same YouTube video:
Does switching a laser on create multiple frequencies?
And it may well be answered here, but I am not conversant in compact support and so forth:
Does switching a laser on create multiple frequencies? Finally, can it be answered without resort to quantum superposition? This answer may well be what I am looking for, but that is not at all evident from my ability to read it:
Frequency Chirp, Instantaneous Frequency and Photons
My question therefore is limited to the observable behavior of a pulse and a prism. Will I observe any spectral spreading of a laser pulse through a prism due to the requirements of df * dt = 1?