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If I have $$ \hat{H} = \int d^3r \hat{\psi}^\dagger(\textbf{r}) H_1(\textbf{r})\hat{\psi}(\textbf{r})$$

How does commutation work with the $\hat{\psi}(\textbf{r})$ with the $H_1(\textbf{r})$? I know the commutator relationship

$$ \hat{\psi}(\textbf{r})\hat{\psi}^\dagger(\textbf{r'}) \pm \hat{\psi}^\dagger(\textbf{r'})\hat{\psi}(\textbf{r}) = \delta(r-r')$$

But I don't know what the commutator is for $H_1$ and $\psi$. I was under the impression that $H_1$ is a scalar number, so I can commute it however, but my notes say to sandwich it between creation and annihilation operators, so I'm not sure how to change the order of terms.

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