In the image :-
R is resistance in the circuit
r is the internal resistance of the battery
E is the EMF of the battery
V is the voltage across the resistor R
Arrows show the direction of current.
If I is the current flowing in the circuit then by Ohm's law I have
I = V÷R and I= (−E)÷r. Now, V/R = (-E/r)
therefore, V= (-E)×R÷r
The problem I'm getting is if r < R , then R/r > 1 which implies V>E.
How is it possible that the voltage across a resistor can be more than the emf of the battery? I must be mistaking somewhere but I'm unable to find it.