# The image charge inside the conducting sphere without producing any electric field [closed]

In the method of images for a grounded conducting sphere, we calculate the position of image charge at $$\frac{R^2}{r}$$, due to which there should be an electric field inside the conducting sphere which violates Gauss' law. I know it's a misconception but I am confused.

## closed as unclear what you're asking by ZeroTheHero, Jon Custer, Buzz, Cosmas Zachos, Kyle KanosFeb 7 at 11:12

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