How do you determine weights from CG when there are more than two locations On the internet they list ways to calculate weights based on CG when there is a weight on the left and on the right of your CG.

Most of the examples show a box truck for determining the weight on the axles.
How would you determine weight when there are 3 points rather than two. I tried looking up how to determine the weights on the axles of a semi-tractor and trailer, but the weight of the front axle seems to always be known.

I would like to suspend this load using springs. So points A, B, and C would be springs in this case. How can I determine the weight on each spring?
The internet seems to have almost nothing beyond the simple A/B example.
 A: The top example is statically determinate. With knowledge of the distances from A and B to the CG you can take the the sum of the moments of A and B about the CG and set to 0. Then sum of the vertical forces $-CG+F_A+F_B=0$ gives you two equations and two unknowns to enable you to solve for the forces at A and B.
For the bottom example, the additional reaction force at C gives you a redundant reaction force to the CG and makes the problem statically indeterminate. It becomes a mechanics of materials problem requiring analysis of the deformations of the three springs and information on the distances between A, B and C with respect the CG and some assumptions about the truck body (e.g., is it rigid, is it to remain level). 
Hope this helps. 
A: Consider converting a simple two-support problem to a mysterious three-support problem.
Suppose you have the load in your diagram supported by $A$ and $B$.  The solution is simple:  $A+B$ must equal the load, and the total moment of the three forces ($A$, $B$, and $\text{Load}$) about any point must be zero.  Two equations, two unknowns, no problem:  a single, unique solution.
Now suppose you decide that the two supports may not be up to the task, and decide to shove another support, $C$, in to help.
So you stick $C$ in, and use jacks or wedges to raise it up to take part of the load.  But you can stop wherever you want!
You can just lightly wedge $C$ in, or you can keep pounding away until $B$ is relieved of almost all  of its load.
Both of these extremes, and everything in between constitutes a valid solution to the question of the value for $A$, $B$ and $C$.
Two equations, three unknowns:  no unique solution.
In the real world, the bed of the truck will flex, the three supports will compress slightly and the load will be shared.  But a simple change in temperature with the attendant thermal expansion of the three load-bearing points, would change this.
