Please explain the dissipation of energy in a circuit containing a resistance and inductor after the switched in the circuit is opened.I mean how do you explain that the energy that is across inductor gets dissipated without any further closed circuit?
A schematic is needed to give a complete answer, but consider the following:
The voltage across an ideal inductor is given by
The inductor will therefore generate a high voltage to resist a large change in current which would be the case in attempting to open the circuit with a switch. If the switch is an air gap type, the inductor will create a high enough voltage to create an arc across the switch contacts, ionizing the air in the gap and allowing current to flow through the ionized air. The energy stored in the inductors magnetic field is thus dissipated in the combination of the arc and the series resistor.
Hope this helps.