When two charged conductors touch, is the charge equally distributed? I understand that if two charged bodies of the same size touch, they will each become equally charged. 

What I am unsure about, is if these bodies are of different sizes (e.g. one is 10x the size of the other), will the charges equally distribute, but then overall the charge on the larger object will be bigger than the charge on the smaller object? 
I have been trying to google an answer to this, but I am not having much luck. Perhaps I just have the wrong keywords and someone can point me in the right direction?
Thank you kindly 
 A: As a result of comments made by @Pieter and @ThePhoton I have updated my answer realising that one cannot solve this problem assuming that one has two spherical capacitors of capacitance $4\pi\epsilon_0a$ and $4\pi\epsilon_0b$ where $a$ and $b$ are their radii resulting in sharing the charge in the ratio of their radii.
Note that in Feynman Volume II Chapter 6 Section 11 that ratio of charge formula is derived (equation 6.35) with the spheres separated and connected with a wire.
He also notes . . . we are interested only in an estimate . . . . . 
The solution to the problem is given in the paper Electrostatics of two charged conducting spheres written by John Leckner.
In Section 4, The repulsive force between two spheres that are or have been in contact, he derives expressions for the charge on the two spheres and then an approximate expression for the ratio of the charge on two spheres of radius $a$ and radius $b$ 
$$\dfrac{Q_\rm b}{Q_\rm a} \approx \left(\dfrac {b^2}{ a^2}\right)\left(\dfrac {\pi^2}{6}\right)^\left ({\frac {a-b}{a+b}}\right )$$ 
He says that this expression is correct if $a=b$ and also when one radius is much bigger than the other.
The maximum error of $2.4\%$ occurs when one radius is four times the other.  
Using this formula it is interesting to see how the simplistic theory $\dfrac{Q_\rm b}{Q_\rm a} = \dfrac b a$ compares with the more sophisticated theory.
$a=b$ gives $\dfrac{Q_\rm b}{Q_\rm a} = 1$
$2a=b$ gives $\dfrac{Q_\rm b}{Q_\rm a} \approx 3.4$
$5a=b$ leads to $\dfrac{Q_\rm b}{Q_\rm a} \approx 18$
$10 a = b$ gives $\dfrac{Q_\rm b}{Q_\rm a} \approx 67$ 
whereas the simple analysis that I first described results in the ratio of charges being $1,\, 2,\,5,\,10$ respectively.  

So the answer to the OP's question is that the larger sphere has more charge on it than the smaller sphere and when the spheres have the same radius they have the same charge on them.
