For a superfluid, we get that the Goldstone modes has a linear dispersion. $\omega=vk$ where $v$ will be a critical velocity. We can have no excitations caused by impurities with a velocity less that the critical one.

This argument seems to hold for all Goldstone modes with a linear dispersion, is it then the case that for linear Goldstone modes imply a superfluid behaviour?


Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Browse other questions tagged or ask your own question.