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The question is:

A pion decays into a muon and a neutrino (which is almost massless, so we’ll take it to have a mass of zero). If the pion is initially at rest, find the energy of the outgoing muon.

Final Answer: $$E_μ=(m_π^2+m_μ^2)c^2/2m_π$$

I used conservation of energy and so the initial energy is just the rest energy of the pion which equals $m_πc^2$ and this should equal the final energy.

Getting the final energy is what I am having trouble with, the mass of the neutrino is approx. 0 so I used the $$E=\sqrt{p^2c^2 + m^2c^4}$$ and crossed out the term with m leaving $E_\nu=pc$. Then, for the muon there is rest energy and kinetic energy I eventually get $$E_μ=m_μc^2/\sqrt{1-u_μ^2/c^2}.$$

However, the final answer neither includes a $p$ nor a $u$, so I think that the problem is in finding the final energy and isolating for the $E_μ$.

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    $\begingroup$ Hi and welcome to physics SE. Please, use laTex notation for formulae. It's about writing them in between of dollar symbols, and laTex commands inside. See here: math.meta.stackexchange.com/questions/5020/… $\endgroup$ – FGSUZ Jan 29 at 0:44
  • $\begingroup$ You are simply forgetting an equation: conservation of momentum $\endgroup$ – Gabriel Golfetti Jan 29 at 0:48
  • $\begingroup$ @GabrielGolfetti That's more like an answer than like a comment. $\endgroup$ – rob Jan 29 at 1:24
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Try to use conservation of momentum to get a new equation. It should eliminate the velocity dependence of the answer.

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  • $\begingroup$ OK thank you, I also realized that for the momentum, I need to isolate pv from the Ev=pv*c equation $\endgroup$ – itiswhatitis Jan 29 at 3:19
  • $\begingroup$ note that $-p_{\mu} = p_{\nu} = E_{\nu} = m_{\pi} - E_{\mu} $ $\endgroup$ – JEB Jan 29 at 3:27
  • $\begingroup$ @JEB can you explain that more? $\endgroup$ – itiswhatitis Jan 29 at 4:29

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