Is the force from an engine constant as a vehicle reaches top speed? I've come across a textbook question and I've got myself confused by it although it seems like it should be simple.
The van accelerates with a (supposedly) constant resistance force up to its top speed. Obviously at top speed the force from the engine is the same as the resistive force. In the real world the resistive force would increase with speed, but why is it the case that the force from the engine will decrease as the speed increases?
The power from the engine is constant, so why isn't the force?

 A: The power equation is typically written as $P=W/t$.  This equation is not easily used when an object such as an automobile is accelerating under constant power, and one wants to know the force involved in that acceleration as a function of time.  Accordingly, this work-time equation can be manipulated in order to derive another equation for power that includes force and velocity:
$P=W/t$
$W=Fd$
A substitution of the work equation into the power equation yields:
$P=Fd/t$
$P=F(d/t)$
Since $d/t$ is equal to velocity,
$P=Fv$
Thus, it is easily seen that under a constant power condition, force decreases as velocity increases, such that
$F=P/v$
A: The acceleration of the vehicle with mass $m$ and power $P$, subject to a constant resistance $F_R$ is
$$ a= \frac{P}{m v} - \frac{F_R}{m} $$
Top speed exists when $a=0$. Otherwise, it is a plug and chug exercise.

Development of the equation above. Take the definition of power $P = F_{\rm E} v$ where $F_{\rm E}$ is the engine force. Combine with $\sum F = F_{\rm E} - F_{\rm R} = m a $ where $F_{\rm E}$ is the force produce by the engine.
