I have a question on the energy of the muons that decay in a plastic scintillator.

In these notes, at page 4, fourth line from the end, it is mentioned that

muons with less than about 50 MeV will stop in the scintillator (about 0.3%.)

It seems that the 0.3% mention is taken from the Bruno Rossi book, High Energy Particles (Prentice Hall, 1952). Unfortunately my local library can't provide me the book.

I would be very grateful = if someone who owns the book could check up if the 0.3 % mention is explained somewhere and share the information with me.

  • 1
    $\begingroup$ I conjecture that it means that 0.3% of the cosmic muons will be below 50 MeV and be caught in the scintilator. see figure 30.5 here pdg.lbl.gov/2017/reviews/rpp2017-rev-cosmic-rays.pdf. Is there no library in your university? $\endgroup$ – anna v Jan 28 at 15:00
  • 1
    $\begingroup$ I agree with @anna's understanding of the meaning of the figure but would mention that the exact value could fairly easily vary by a factor of two in either direction depending on local latitude and elevation (it depends a lot on the local height an density of the atmosphere). $\endgroup$ – dmckee Jan 29 at 0:16

Your Answer

By clicking "Post Your Answer", you acknowledge that you have read our updated terms of service, privacy policy and cookie policy, and that your continued use of the website is subject to these policies.

Browse other questions tagged or ask your own question.