# Is the *measured* temperature inside a hollow black body the same if we place a thermometer inside it or let it make contact with the body itself?

Imagine the inside of a black body shell with non-zero thickness. Inside the shell, there is photon gas produced by the shell [at a temperature much higher than zero, say $$1000(K)$$]. Is there is a temperature difference (which objectively there is not, but according to the thermometer) between placing the thermometer somewhere in the shell and bringing the thermometer in direct contact with the shell? Obviously, the two means of heat transfer (radiation and heat conduction) are different from each other. Is the temperature of the photon gas (as indicated by the thermometer) lower because not all energy that hits the thermometer (by means of the photons) is absorbed by it, while all the energy transferred by conduction to the meter is absorbed?
Please correct me if I'm wrong.