Why is the MKS unit of time the same as the CGS unit? [closed]

There are many system of units used in physics. In the CGS, the units are,

• length : centimetre

• mass : gram

• time : second

And in the MKS system the units are,

• length : metre

• mass : kilogram

• time : second

Though other units change in different systems, but time's unit never changes. Why?

closed as off-topic by FGSUZ, Bill N, Buzz, Kyle Kanos, Jon CusterJan 14 at 14:15

• This question does not appear to be about physics within the scope defined in the help center.
If this question can be reworded to fit the rules in the help center, please edit the question.

• I don't think this can be answered (but I may be wrong). Time has always been special with regard to larger intervals than seconds (no kiloseconds etc.). – Jasper Jan 13 at 12:24
• This is not a physics question. The choice of units is just arbitrary. You can create a $MKM$ system if you want to.. – harshit54 Jan 13 at 13:11
• I'm voting to close this question as off-topic because I think it belongs to hsm.stackexchange.com – FGSUZ Jan 13 at 23:06
• It is a mistake to think Giorgi's choice was just arbitrary, and not a physics question. On the other hand, the question may belong to HSM. – jkien Jan 13 at 23:29
• Making inferences off a sample of size 2 can be dangerous. Just take a gander at the Wikipedia entry on 'natural units' and see that the time units are not necessarily seconds. – Kyle Kanos Jan 14 at 11:16

Giorgi noticed that a small change in the prefixes of the base units of CGS could achieve coherence with the joule. His new base units were decimal (sub)multiples of the old base units, and only one of the base units had a prefix, similar to CGS. So the unit of length lost its prefix, $$cm \rightarrow m$$, while either the unit of mass or the unit of time obtained a prefix.
Giorgi's solution was to change the unit of mass: $${joule} = [M]\ m^2\ s^{-2} \rightarrow [M] = 1\ {kg}$$
Trying to change the unit of time did not result in a decimal (sub)multiple of the second: $${joule} = g\ m^2\ [t]^{-2} \rightarrow [t] = 10^{-1.5}\ second$$