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After a star lives and dies, I assume virtually all of its mass would be photons. If enough stars have already lived and died, couldn’t there be enough photon energy out there to account for all the "missing mass" (=dark matter) in the universe?

And if there were enough photons to account for all the missing mass, what would it look like to us?

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    $\begingroup$ Only a tiny fraction of a star's mass ever converts into photons. $\endgroup$
    – David Z
    Commented Nov 29, 2012 at 7:28
  • $\begingroup$ Cosmologists do take the photons into account in their calculations. However, the energy of all the photons emitted by stars, and even those emitted in extreme events like supernovae and black hole accretion processes, is relatively small. The photon energy in the universe is predominantly that of the CMB. $\endgroup$
    – PM 2Ring
    Commented Sep 17, 2018 at 18:06
  • $\begingroup$ @DavidZ: The CMB is not starlight. It predates star formation. $\endgroup$
    – user4552
    Commented Sep 17, 2018 at 18:54
  • $\begingroup$ @BenCrowell I know, I wasn't talking about the CMB and it didn't seem like Tom was either. In any case, these comments shouldn't really be comments so I'd like to come back and delete them after a while. $\endgroup$
    – David Z
    Commented Sep 17, 2018 at 19:47

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As a general rule, zero mass particles which travel with the velocity of light are not good for dark matter, because dark matter concentrates around gravitational attractors. It has to be particles with some mass that can be at rest in order to stay around a galactic center from the beginning. In addition they have to be controlled by weak interactions, if they decay, because the dark matter halo is stable for long periods.

Maybe I should add that very cool photons from the beginning of the formation of the observed universe exist and have been detected as Comsmic Microwave Background radiation, very low frequency photons, uniformly distributed in the cosmos.

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    $\begingroup$ Thanks for your answer. If there were a sea of photons, would they not also concentrate around gravitational attractors? Wouldn't there be more photons in the potential energy well of the gravitational attractor than there would be in flat space? Wouldn't this situation be stable? Are particles with mass really the only candidates? $\endgroup$ Commented Nov 29, 2012 at 6:52
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    $\begingroup$ Aside from the unstable orbit at $r = 3M$ you can't bind photons in a gravitational well. The reason is simply that they always travel at $c$, while particles with mass can take any speed. That's why planets can have stable orbits round the Sun. There is a single distance from a mass where the velocity of light matches it's orbital velocity, but even this orbit is unstable so you'd never find any significant concentration of photons there. $\endgroup$ Commented Nov 29, 2012 at 7:15
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    $\begingroup$ As John says; a particle has to have some mass to stay at an orbit.CMB does not concentrate around galaxies, and that is the coldest photons we have observed, because they still travel at the velocity of light. $\endgroup$
    – anna v
    Commented Nov 29, 2012 at 7:31
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There is a simple argument why photons emitted by stars can't be dark matter, and that's because there is about ten times more dark matter than normal matter. If all the stars created at the Big Bang had turned into photons there still wouldn't be enough of them.

You might argue that maybe more normal matter than we think was created during the Big Bang, but the theory of Big Bang Nucleosynthesis places a limit on how much normal matter was created, and this limit is four times smaller than the amount of dark matter. The dark matter has to be something odd.

If you're interested in more info this paper is a good review, though harder going than the answers here!

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Photons are easily detectable. We can count how many photons are there at any distance of us by just counting the photons reaching us from there. It is impossible that the hidden photons ramble the whole universe but mysteriously avoid us.

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  • $\begingroup$ It isnt true. If the photons are of a extremely low frequency, you could only detect that photons using an extremely large antenna, which cant be built .This kind of photon may be the one that make thes EMDrive work $\endgroup$ Commented Jun 26, 2019 at 1:34
  • $\begingroup$ @Sartem Cacartem The photons from star collapses anyway will be of higher frequency than CMB. $\endgroup$
    – Anixx
    Commented Jun 26, 2019 at 1:38
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I just want to point out that it seems some people may be conflating 'dark matter' with 'dark energy.' Regular "normal" matter like electrons, neutrons, and the like, are estimated to make up about 5% of the matter/energy density of our universe.

Dark matter, estimated to make up about 25% of the matter/energy density of the universe, is matter that has mass, but the gravitational and other effects of which are not directly visible. Dark matter is somewhat mysterious but could easily be something like exotic particles or oceans of black holes between galaxies.

Dark energy, is the real mystery; it makes up the other (about) 70% of the matter/energy density of the universe needed to explain inflationary cosmology and expansion/acceleration of the universe.

Photons are mass-less particles that embody energy, visible when they strike objects. I think it's an interesting notion that the energy from photons could at least in part constitute some of solution to the "missing" dark energy problem. As has been pointed out, it's difficult to reconcile how so much of the "missing" energy could have come from so little: the 5% ordinary matter creating all that dark energy. But I don't see anything impossible about this idea generally. Perhaps the dark matter also contributes to this somehow. There may even be dark-electromagnetic forces that create dark-photons, this may be seen as extra-dimensional as one poster referenced earlier.

"It’s humbling to think that ordinary matter, including all of the elementary particles we’ve ever detected in laboratory experiments, only makes up about 5% of the energy density of the universe." _Sean Carroll

With so little of what we are used to seeing and interacting with in ordinary meaningful way actually making up what exists, speculation of what else is out there is not only justified but necessary.

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Photons don't have mass. So your assumption's incorrect, although I don't know how much of a (say) main sequence star's mass gets converted into photons over its lifespan.

Photon's can't account for, say, dark matter, because dark matter has mass.

Thermal energy (in the vacuum) is comprised of photons, which can spontaneously form particle-antiparticle pairs. Usually these quickly annihilate, so this is also not a good source of mass.

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    $\begingroup$ -1. Photons don't have mass, but they do have energy. It is fully possible that during a star's lifespan, some amount of it's mass is converted into energy (i.e., photons). $\endgroup$
    – Kitchi
    Commented Nov 29, 2012 at 6:32
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    $\begingroup$ The assumption was that all a star's mass is converted to energy in the form of photons. Humor me for a moment. You say dark matter has mass. How do you know? Is it because it affects gravity? Do we know for certain that photons do not affect gravity? $\endgroup$ Commented Nov 29, 2012 at 6:44
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    $\begingroup$ Photons do affect gravity, but that's because gravity is affected by energy, not mass. $\endgroup$
    – David Z
    Commented Nov 29, 2012 at 7:28
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    $\begingroup$ Photons do affect and are affected by gravity ( gravitational lensing) they cannot be captured by gravitational wells because of the velocity c. See Johhn's comment in my answer. $\endgroup$
    – anna v
    Commented Nov 29, 2012 at 7:33
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    $\begingroup$ @Ryan - yes, in the absence of mass gravity is affected by energy and even unlikely things like pressure. The source of the curvature is the stress-energy tensor (en.wikipedia.org/wiki/Stress%E2%80%93energy_tensor) and this makes no distinction between mass and energy. They are treated as related by the (in)famous $E = mc^2$. $\endgroup$ Commented Nov 29, 2012 at 10:50
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It is accepted that the early state of the universe was mainly radiation, then we had expansion; radiation cooled down as a result, and condensed into matter. The pressure of a photon/radiation gas is positive and given by an equation that resembles the universal gas law; PV=.9 NkT (https://en.wikipedia.org/wiki/Photon_gas). So by logic, the total(equivalent) mass or the total condensed energy in the universe, must be less than the total radiation at the start. If also the condensation process involved only a small portion of that radiation, then surely we should have plenty of radiation left uncondensed- and could easily be much more than that of all matter. This remaining gas is continuing its expansion of course- today and in the future.Since momentum levels follow energy levels for photons, there must be plenty of momentum around too- due to radiation that is exerting pressure on the various matter objects, producing some expected and may be not so expected situations. If we accept this point of view, one can do detail calculations to get the full picture. The rate of expansion could be one useful result to compare with present data.

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