You are correct.
There are a number of ways of looking at the situation.
Assume that there is a magnetic field $\vec B$ into the screen and the whole circumference of the loop is moving inwards at a speed $\vec v$.
The direction of the induced current can be deduced from the right hand grip rule knowing that Lenz's law predicts that the magnetic field produced by the induced current will be in such a direction as to reduce the change producing it which is a reduction in the magnetic flux through the loop.
The induced magnetic field is into the screen and the induced current is clockwise.
A charge $q$ within the loop moving inwards at a velocity $\vec v$ experiences a Lorentz force $q \vec v \times \vec B$ in a direction as shown in the diagram.
This results in the direction of the induced (conventional - as if the mobile charge carriers were positive) current being clockwise.
Now you have an induced current-carrying conductor moving inward at a speed $v$ in a magnetic field $\vec B$.
There is therefore a force on the conductor radially outwards.
To maintain the radially inward constant speed motion of the loop an external force needs to be applied radially inwards and this external force does work as the4r loop moves inwards.
The work done by the external force results in the generation of the induced current which when passing through the loop which has resistance produces a heating effect.
This is the law of conservation of energy in action with the work done by the external force ultimately producing heat.