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This is a followup question to the answer given to a similar question where the velocity is given as

$$v(r) = \left(1 - \frac{r_s}{r}\right)\sqrt{\frac{r_s}{r}}c \tag{1}$$

where $r$ is the radius from the Schwarzschild co-ordinates and $r_s$ is the Schwarzschild radius.

What would be the velocity depending on $t$, the co-ordinate time, i.e.

$$ \frac{dr(t)}{dt} = \;?$$

Looking at the Wikipedia link given in the referenced answer, section "Local and delayed velocities" I would guess it is

\begin{align} \frac{dr(t)}{dt} &= \frac{dr}{d\tau}\frac{d\tau}{dt}\\ &= v_{\parallel}\gamma\sqrt{1-r_s/r}\cdot\frac{1}{\gamma} \sqrt{1-r_s/r}\\ &= v_{\parallel}(1-r_s/r) \end{align}

but I can't find what $v_{\parallel}$ is.

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  • $\begingroup$ I wrote that section about the local and delayed velocities, $v_{\parallel}$ is meant to be the radial component, and $v_{\perp}$ the transverse component of the local velocity relative to a Fido. That is also mentioned in that section. $\endgroup$ – Yukterez Sep 7 at 3:20
  • $\begingroup$ @Yukterez What is a Fido? $\endgroup$ – PM 2Ring Sep 7 at 5:15
  • $\begingroup$ see universeinproblems.com/index.php/… and perimeterinstitute.ca/images/files/… - that's simply a local observer who is stationary with respect to the central mass $\endgroup$ – Yukterez Sep 7 at 9:53
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The Schwarzschild metric in Schwarzschild coordinates $(t, r, \theta, \phi)$ shows
$ds^2 = -(1 - 2M/r) dt^2 + (1 - 2M/r)^{-1} dr^2 + r^2 (d\theta^2 + \sin^2\theta d\phi^2)$
where:
$c = G = 1$ natural units
$M$ black hole mass
$r_s = 2M$ Schwarzschild radius (event horizon)

If we drop an object at rest from infinity, we have a radial free fall $(d\theta = d\phi = 0)$ where
$dt = (1 - 2M/r)^{-1/2} d\tau_{stat}$ time dilation measured at infinity (far away from the horizon) vs. the proper time of a stationary observer at Schwarzschild radial coordinate $r = constant$
$dt = \gamma (1 - 2M/r)^{-1/2} d\tau_{free fall} = (1 - 2M/r)^{-1} d\tau_{free fall}$ time dilation measured at infinity (far away from the horizon) vs. the proper time of a radially free falling object
$\gamma = (1 - v^2)^{-1/2} = (1 - 2M/r)^{-1/2}$ Lorentz factor of a radially free falling object vs. a stationary observer at Schwarzschild radial coordinate $r = constant$
$v_{stat} = (2M/r)^{1/2}$ velocity relative to a stationary observer at Schwarzschild radial coordinate $r = constant$
$v_{Schw} = (1 - 2M/r) (2M/r)^{1/2}$ velocity relative to Schwarzschild coordinates

Coming to your first question, $dr/dt$ is $v_{Schw}$, i.e. the velocity measured in Schwarzschild coordinates. In the post it is equation (1).
As for your second question, $v_{\parallel}$ is $v_{stat}$, i.e. the velocity relative to a stationary observer.

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