# Simultaneous measurements in Quantum Mechanics

In the notes I am using, it states that if two observables A and B are measured simultaneously, then the measurement of A does not affect the measurement of B, and vice versa. However, why does the frame of reference seem to be neglected in this explanation? For another observer, it seems that if A and B are measured simultaneously in the first frame, they will not be simultaneously measured in the second frame; thus the measurement of B should affect the measurement of A? Is this due to some change in the observable due to the relative motion that I am not aware of?

• Can you provide more context? In particular, are the measurements of A and B performed on the same system? – probably_someone Dec 12 '18 at 18:46
• Although not specified in the notes, I would assume that they are? – EigenFunction Dec 12 '18 at 19:20
• Also, is there a reason to suspect that these notes are using a relativistic extension of quantum mechanics? Because if not, quantum mechanics is non-relativistic, which means there's an absolute notion of simultaneity. – probably_someone Dec 12 '18 at 19:27
• It’s possible the notes do not account for relativity, since I don’t seem to see any mention of it; however, why would this not lead to paradoxes if the process of measurement is non-commutative? – EigenFunction Dec 13 '18 at 1:47
• Which notes? Which page? – Qmechanic Dec 20 '18 at 20:05

That is, if we observe an event $$A$$ influencing an event $$B$$ at a space-like separation, there will be a frame in which this will look like instantaneous action at a distance, and in every physical frame this will look as an influence propagating at superluminal speeds. In other words, for causality, you have to require no influence of measurements over space-like separations, and this is indeed one of the building blocks of quantum field theory, the relativistic extension of quantum mechanics.