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In Dark Matter Indirect Detection literature, it is usually said that the relative velocity of dark matter particles in the galactic halo is about $$ v \sim 10^{-3}c$$ See for an example this lecture notes

I am wondering how one derives this result?

Any helps or comments would be appreciated.

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The number above is derived simply from the speed of our Sun and solar system with respect to the Galaxy.

The dark matter is expected to form (to first order) a virialized, non-rotating, smooth halo in which the visible matter of the Galaxy is embedded. In that respect it is quite similar to the other Galactic halo components (globular clusters etc.), that form a spherical distribution around the Galaxy with little net rotation. In this model the dark matter has a $\sim$ Maxwellian distribution, with an average velocity of zero and a velocity dispersion at the solar radius of around 200 km/s. The velocity distribution will be truncated at around 600 km/s by escape from the Galactic potential.

The solar system travels in an orbit with a speed of about 240 km/s ( $8\times 10^{-4}c$) with respect to a non-rotating Galactic frame. It therefore would encounter dark matter with an average speed of $\simeq 270$ km/s but with a minimum speed of zero and a tail out to around 800 km/s.

This first order model is complicated by possible substructure in the dark halo, tidal streams and the assembly history of the Milky way. At the Earth it would also be modulated by $\pm 10$% by the Earth's orbital motion and gravitational focusing by the Sun (see Freese et al. 2012 for much more detail).

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  • $\begingroup$ Thanks for your answer. So, why do we consider dark matter to form a non-rotating halo? I mean why dark matter is not rotating around the center of the galaxy, similar to the luminous matter? $\endgroup$
    – Ramtin
    Commented Nov 27, 2018 at 5:45
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    $\begingroup$ @Ramtin It is similar to the halo population of stars in our Galaxy. en.wikipedia.org/wiki/Galactic_halo The net rotation will likely not be exactly zero, but it will be small. $\endgroup$
    – ProfRob
    Commented Nov 27, 2018 at 8:59

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