# Finding the unit of Pressure/Volume

Me and my friend are trying to find the exact unit of Power=Pressure/Volume. We know that the unit has to be W(J/s) so we try from the equation above: (Kgm²/s³)=(N/A)/V The right side will be: (Kgm/s²)/m^5 Then, Kg/(s²m⁴) So at the end: (Kgm²/s³) ≠ Kg/(s²*m⁴). Are we missing something?

We know we can get the exact unit using: W=F×x ==> F=W/x And etc... But we want to know why the first way is wrong? The example we are trying to solve

• power$\ne$pressure/volume but work = pressure $\times$ volume – Farcher Nov 22 '18 at 9:20
• Even if we say that W=P/V. (Kg*m²/s²) = (N/A)/V... The final result will be the same as above, the m⁴ wil still down – GalaxyLimits Nov 22 '18 at 9:29
• Malwarebytes blocks the website in your link for me. As @Farcher says, you can't get this to work out, because "Power = pressure/volume" is just plain wrong. – alephzero Nov 22 '18 at 9:41
• Power=Pressure/Volume is wrong, and you have taken W=P/V as argument in your comment,whereas it should be W=P*V. – Blazar Nov 22 '18 at 9:48
• Oh, I see! Our doctoe told us something like a relation between Power and pressure over volume and in his slides (the one that he have) the relation is wrong. Thank you all for the answer. – GalaxyLimits Nov 22 '18 at 10:09