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How to diagonalize a hamiltonian matrix that has differential operators as elements? My matrix looks something like: \begin{bmatrix} A \frac{d^{2}}{{d\theta}^{2}}+ B_{1} & a\cos{(b\theta +c)}\\ a\cos{(b\theta +c)} & A \frac{d^{2}}{{d\theta}^{2}}+ B_{2} \end{bmatrix} where A, $B_{1}$, $B_{2}$, a,b and c are all constants. How to do I find the spectrum of eigen values for such systems. Are there any standard methods available.

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Let your matrix operate on a vector of functions (of $\theta$, in this case), and look for solutions where it produces a constant multiple of that vector. In other words, solve

\begin{equation} \begin{bmatrix} A \dfrac{\mathrm d^{2}}{{\mathrm d\theta}^{2}} + B_{1} & & a\cos(b\theta +c) \\ a\cos{(b\theta +c)} && A \dfrac{\mathrm d^{2}}{{\mathrm d\theta}^{2}}+ B_{2} \end{bmatrix} \begin{bmatrix} f(\theta)\vphantom{\dfrac{\mathrm d^{2}}{{\mathrm d\theta}^{2}}} \\ g(\theta)\vphantom{\dfrac{\mathrm d^{2}}{{\mathrm d\theta}^{2}}} \end{bmatrix} =\lambda \begin{bmatrix} f(\theta)\vphantom{\dfrac{\mathrm d^{2}}{{\mathrm d\theta}^{2}}} \\ g(\theta)\vphantom{\dfrac{\mathrm d^{2}}{{\mathrm d\theta}^{2}}} \end{bmatrix} \tag{01}\label{eq01} \end{equation} which is a coupled set of second-order differential equations for $f(\theta)$ and $g(\theta)$. To help solve this system and find values of $\lambda$ which produce periodic solutions so that there is no discontinuity in $\theta$, read about Mathieu functions.

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  • $\begingroup$ Could someone who knows LaTeX better than I do tell me how to make the matrix brackets and the vector brackets the same height? $\endgroup$ – G. Smith Nov 17 '18 at 4:07
  • $\begingroup$ How can I diagonalise such a matrix? I found something called Fulton-Gouterman transformation. $\endgroup$ – EverydayFoolish Nov 17 '18 at 5:05
  • $\begingroup$ Sorry, I don't know anything about that transformation. But if you can find the operator's eigenvectors and eigenvalues, you can diagonalize it. Unfortunately, I think I'm wrong about the Mathieu functions... I originally didn't notice that the $B$'s had subscripts, and when I took $B_1=B_2=B$ and decoupled the equations by looking at $f+g$ and $f-g$ I got Mathieu functions. But for the more general $B_1\ne B_2$ I get fouth-order PDEs that I don't know how to solve analytically. Are you trying to get an analytic solution or a numerical solution? $\endgroup$ – G. Smith Nov 17 '18 at 5:28
  • $\begingroup$ With Mathematica, I can numerically find the eigenvalues and eigenvector functions using the function NDEigensystem. For example, for $A=B2=B2=a=b=1, c=0$, I get that the first five eigenvalues are -0.2932, -0.2932, 0.405184, -1.28535, and -1.34277. $\endgroup$ – G. Smith Nov 17 '18 at 6:05
  • $\begingroup$ Any idea on how i could decouple them or resource where I can read about solving coupled differential equations $\endgroup$ – EverydayFoolish Nov 17 '18 at 14:43

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