# A question about almost stationary orbits

For an orbit around the earth with period equal to a sidereal day with eccentricity $$e=0$$ and inclination $$i=0$$, the path on earth would be a single point on the equator. I have done some simulations that suggests that if $$e>0$$ and $$i>0$$ the path would take the form of the figure '8'. If $$e\gg 0$$ one loop in the figure would be less than the other and greater $$i$$ gives a taller '8'.

My question is: what would the figure be if $$e=0$$ and $$i=90^{°}$$?

• Intuitively, a large circle, but hopefully someone can do the math. See the Analemma Tower project: dezeen.com/2017/03/23/… Nov 13, 2018 at 22:13