Is the uncertainty principle a circular argument? [closed]

Uncertainty is due to the measurement techniques humans tend to use requiring photoelectric effect. The Planck constant is due to the photoelectric effect. If the standard deviation of measurement was zero, both sides of the equation would be zero and the uncertainty equation would be meaningless. So it has already been assumed for uncertainty to work.

closed as unclear what you're asking by Aaron Stevens, Jon Custer, Dale, John Rennie, Kyle KanosNov 13 '18 at 22:33

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• Can you expand on your reasoning here? What equation are you talking about? Why are you only focusing on the photoelectric effect? Also, realize that the uncertainty principle is independent of our measurement techniques. – Aaron Stevens Nov 13 '18 at 2:09
• Then it doesn't mean anything because the standard deviation can be zero – Liu Nov 13 '18 at 2:24
• I still don't understand what you mean. – Aaron Stevens Nov 13 '18 at 2:30
• The uncertainty principle says that uncetainty exists if uncerainty exists – Liu Nov 13 '18 at 15:58
• I understand that is what you are saying, but I don't follow your reasoning. Can you please expand on it. – Aaron Stevens Nov 13 '18 at 16:12

If you want to understand how we got to the uncertainty principle: $$\Delta x \Delta p \geq \frac \hbar 2,$$ there are lots of great resources to start with only a Google away.