# Current as a function of time RL-circuit [closed]

The switch, S, in the circuit has been open for a long time. At t=0 it suddenly closes. Calculate the current through the inductor, $$I_L$$, as a function of time. Resistance in the inductor can be neglected.

I am trying to understand what the flow of the current will look like at different $$t$$s. At $$t<0$$, the switch is closed and the inductor is at steady state, does the current not flow through the second resistor at this point? And when $$t>0$$, do you only focus on the right part of the circuit with the inductor and second resistor?

Or can I just ignore the second resistor?

## closed as off-topic by ZeroTheHero, John Rennie, Emilio Pisanty, user191954, Kyle KanosNov 14 '18 at 12:34

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