The switch, S, in the circuit has been open for a long time. At t=0 it suddenly closes. Calculate the current through the inductor, $I_L$, as a function of time. Resistance in the inductor can be neglected.
I am trying to understand what the flow of the current will look like at different $t$s. At $t<0$, the switch is closed and the inductor is at steady state, does the current not flow through the second resistor at this point? And when $t>0$, do you only focus on the right part of the circuit with the inductor and second resistor?
Or can I just ignore the second resistor?