Below shown is a setup, and block B starts from rest and moves towards right with a constant acceleration. Does the acceleration differ for the blocks ? I am a bit confused because of the tricky string setup. If after time t, the velocity of A with respect to B becomes v, then what would be the acceleration of A ?

My understanding is : After time t, Block B will be brought to rest instantaneously resulting in non-zero relative velocity which otherwise will continue to be 0.

Block String Setup


I do not think it is that tricky. For each pulley you have an equation relating the speed of the rope in, the speed of the rope out and the speed of the pivot. The speed of the pivot is the average of the two speed ropes.

Here are the kinematics of the system

$$ v_E = 0 \\ v_B = a t \\ v_C = v_B \\ v_B = \frac{v_D+v_E}{2} \\ v_A = \frac{v_C+v_D}{2} $$

If you notice there are five equations, with five unknowns ($v_A$, $v_B$, $v_C$, $v_D$, $v_E$).

The answers I get are:

$$v_A = \frac{3}{2} v_B \\ v_B = a t \\ v_C = 0 \\ v_D = 2 v_B \\ v_E = 0 $$

| cite | improve this answer | |

Your Answer

By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy

Not the answer you're looking for? Browse other questions tagged or ask your own question.