I had asked this question:No matter the arrangement of resistors in a circuit, a battery will still produce a current as if it were connected to an imaginary combination of the individual resistors within the circuit? Can anyone explain why this is so, can the charged particles know there is a resistance before they leave the power supply? when I was learning electric circuit basics. I now believe I have an answer for it, but I do not know if it is wholly correct.
So, when a battery is connected to a circuit with a resistance of let's say $R$. The potential difference is established within the circuit almost at the speed of light. For a negligibly short amount of time, the current is not homogenous within the circuit, since there are also particles within the wires or resistance. The particles which initially leave the battery with a specific speed are faster than the particles which are already found in the wires, since they were not charged in the battery. The charges leave the battery in a certain amount of time, however, they lose some time over the resistance and this causes charge to accumulate. However, after this almost instantaneous moment, the charges which left the battery enter it in a certain time, lets say tx and the battery also produces charge q over time tx. Is this a correct understanding of this question?
If you could not understand what I have stated above, here is a much simpler version. Which explains why current does not pass through a resistance if there is another path w/out resistance.Let's suppose that a single battery is connected with a wire, which does not have resistance. Electrons will start to flow , in reality, with a wire with resistance, a potential difference would be generated across it. The current would build up until the potential difference is equal to the voltage of the battery. In the case in which potential difference is not created by the wire because there is no resistivity, the potential difference across will immediately become equal to that of the battery.