# Binding energy of the nucleus

In a reaction U235+1n->141 Ba +92Kr +(3) 1n+200MeV, the energy released (200Mev) is of one atom or of 6.023*10^23 atoms?

• note that 200 MeV is around $10^{-23}$ kilotons of TNT (not a coincidence that the kT is the preferred unit of these devices, I mean with the 23 in the exponent and all). – JEB Oct 20 '18 at 12:51

$$200*6.023*10^{23} eV =200*1.6*6.023*10^{4}J$$
• Yes. And if you want the energy in Joules, then multiply by $1.6*10^{-19}$ – Mechanic7 Oct 20 '18 at 12:58