I have the above circuit, and the current through the ammeter is 0A. But why is this the case? Is there any way I can easily show that the potential difference across that segment is 0V?
Also, the solution simply says that this is a balanced Wheatstone bridge, with that being the reason for I = 0. But why exactly is this the case? I can't really see any similarity between this and the balanced bridge except that the current through one segment is zero.