Electroweak to Electro/Weak Bosons? I apologise in advance, this is something I just can't seem to get my head around. So it's my understanding that before the electroweak force split, there were four bosons - $W^1$, $W^2$, $W^3$ and $B$ - and that they mix or interact to form photons $\gamma$, $W^+$/$W^-$ and $Z$ bosons. So, in our current universe with the split weak nuclear and electromagnetic forces, what happens to $W^1$, $W^2$, $W^3$ and $B$? If photons are mixes of $W^3$ and $B$, does that mean the $W^3$ and $B$ bosons are created for an instant and then mix to form a photon in the heart of a star? Or can photons be made without W3 and B?  
 A: I had the same question about a month ago when i tried to interprete the mathematics of electroweak SSB(sponteneous symmetry breaking). I investigated the obvious resolutions: either [1]maths is givining wrong interpretations or [2]It is giving correct interpretations.
Since Standard Model of EW interaction is so profound, I assumed [2] is correct.
So, what is the interpretation then if we analyze the math?
Consider this (understand in terms of fields, which are more fundamental than particles):
[a]Before SSB, above electroweak unification energy($E_{ew}$), we had 4 fields. 
[b]At $E_{ew}$, these 4 fields start interacting with each other and mix in different combinations. 
[c]After SSB, we have 4 new fields.
{$E_{ew}$ is about 246 GeV(approximately $10^{15}$ K, a temperature exceeded until shortly after the Big Bang)}
i.e., the real world is energy dependent. The cases [a], [b] and [c] do not exist together.
The fields in [c] are completely new and its like resultant fields of combinations.
And Our current stage of the universe falls under [c], therefore only [c] fields exist.
"what happens to $W^1$, $W^2$, $W^3$ and $B$?"
These fields do not exist in this stage of the universe.
"does that mean the $W^3$ and $B$ bosons are created for an instant and then mix to form a photon in the heart of a star?"
No!. Only photons are created directly. The reason is that $W^3$ and $B$ fields do not exist in this stage and therefore we can't have $W^3$ and $B$ quanta. Only $A$ and $Z$ fields exist.
