First of all, the space $X$ here is the Hilbert space $\mathcal H$ of the system, since the $U(1)$ transformations apply to the state vector $|\psi\rangle \in \mathcal H$ of the system. "Isotropic" is not the correct term to describe the symmetry. The term "isotropic" could maybe be used if $\mathcal H \cong \mathbb C^N$ were symmetric under $SU(N)$ transformations, but I don't think this is a common terminology (also, such a system would be very boring). Instead, this is called a (global) $U(1)$ gauge symmetry.
Let me make two more comments. First, the two symmetries here have an important fundamental difference. The $SO(3)$ symmetry of mechanics compares actual, physically different system states (different rotations of the physical system). However, the $U(1)$ symmetry of quantum mechanics is a gauge symmetry, meaning: The two states $|\psi\rangle$ and $e^{i\varphi} |\psi\rangle$ are the exact same physical state, but our description of the system allows that same state to be described with many different Hilbert space vectors. (This is for convenience only, the actual state space is $\mathcal H / \mathbb C^\ast$, but it is easier to work with $\mathcal H$.)
Second, the Noether theorem states that every symmetry corresponds to a conserved quantity. The conserved quantity corresponding to the $SO(3)$ symmetry of mechanics is angular momentum, but what is that of the $U(1)$ gauge symmetry? Once you learn about QED, you will see that it is the total electrical charge.