# Gamma ray spectroscopy lab experiment : Cobolt 60 Data

I am currently carrying out an a gamma ray spectroscopy experiment. At this moment in time I am trying to decipher what parts of the gamma spectrum are what, i.e Compton edge, backscatter, photo peaks and trying to really relate the physics to the data, but I am having some issue with that.

Here Is my current graph From the graph I can clearly see the two photo peaks which should be expected from the decay of cobalt, but it the other two peak I am not really sure about.

Starting with the largest peak $$(-5.4,408)$$, in my lab the demonstrators told me that was the Compton edge on the graph, which is what I understand to be that within the scintillator Compton scattering occurs except that the gamma photos escape from the scintillator and we are left with only the energy of the electron.

But my issue is that looking at point (667.1,101) this to me look like a backscatter peak, which mean that some of the photons are being scattered outside the detector and then only some of the energy of the photon is actually making it way back into the detector.

My question is, is it possible to have a backscatter, of higher energy than the Compton edge, or is there other process coming into play for example like characteristic x-rays, during photoelectric absorption?

For some reason my intuition tell's (which could be wrong) me that you cant get Compton edge at a lower energy than you can a backscatter peak,the reason for this is that Compton scattering is dependent on the angle and that within the detector you more likely going to more energy loss with in the detector than outside of it due to the electron density of the scintillation material.

The useful form of the Compton formula (rather than that $$1/\lambda$$ version) is $$E={E_0 \over 1 +{E_0 \over m_ec^2}(1-\cos\theta)}$$, and you get the Compton edge energy by putting $$\cos \theta=-1$$