# Electric flux through gauss law

Why is it that objects kept in uniform electric field have net flux through them when gauss law says that net flux through a surface is q/epsilon.I mean the net charge will be zero if a gausian surface is drawn so the net flux must also be the same

Gauss's law says that the net flux through a closed surface is equal to $$q/\epsilon_0$$ where $$q$$ is the charge enclosed in the surface. Gauss's law would not make sense for open surfaces that don't enclose a volume. For a uniform electric field, any closed surface will have equal number of field lines entering the surface as exiting the surface and so the total flux across that surface will be 0 as required.