# Question on relative velocity [closed]

If a man is moving on a horizontal belt (with constant velocity w.r.t belt)which is also moving in the same direction with some velocity , then time w.r.t belt and w.r.t ground to travel some distance on the belt is coming different, how is.this possible?

Time w.r.t belt = distance/velocity of man w.r.t belt

Time w.r.t ground = distance/velocity of man w.r.t belt+ velocity of belt

How.can the two times be different as time does not depend on reference frame

## closed as unclear what you're asking by John Rennie, Bill N, ZeroTheHero, Kyle Kanos, Jon CusterSep 18 '18 at 13:05

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• Your wording is a little unclear. Do you want to ask how it is possible to move, say, 10 meters with respect to the ground in different time to 10 meters with respect to the belt? – user93146 Sep 14 '18 at 13:45
• the times do not add linearly, they add harmonically. That is, the rates add linearly. – JEB Sep 14 '18 at 15:34

time w.r.t. belt = $\frac{distance..w.r.t..belt}{velocity..w.r.t...belt}$.
Not $\frac{distance..w.r.t..ground}{velocity..w.r.t..belt}$.