Why is the internal pressure against the nozzle body not included in calculating the anchor force? 
Why is the internal pressure against the nozzle body not included in calculating the anchor force?  The attached picture shows all of the forces acting on the body.  But I would assume the pressure on the angled walls of the nozzle would cause a force in the downward direction of F= Pressure * sin(wall angle) * area.  From all examples of this nothing I can nothing factors this in and I do not fully understand why. 
Thanks for your help!
 A: The figure shows the forces acting on the fluid, not on the nozzle body.  The anchoring force is what the nozzle has to exert on the fluid to satisfy the macroscopic momentum balance on the fluid.  This force is equal and opposite to the force the fluid exerts on the nozzle, and automatically includes the pressure the fluid exerts on the nozzle.
A: Imagine for simplicity that the nozzle is closed. 
What force is exerted on the nozzle by the water?
It is the weight of the water, $W_w$, plus the pressure force $p_1A_1$. That's it.
There is no additional force $F$ acting on the angled wall - it is just a fraction of the combined force we've identified, applied to the wall. The rest of the combined force will be applied to the closed bottom of the nozzle. If the nozzle was replaced by a cone $(A_2=0)$, all combined force would be applied to its wall.  
A: The exit conditions are given here, which are actually dictated by the shape of the nozzle, hence when you are calculating the anchor force from inlet and exit conditions, the influence of nozzle shape is already considered. 
